When to return null in React render function

Last updated : December 15, 2022

React components can also perform side effects instead of rendering something to the screen. For example, insert a script to the page or insert a listener to some events. In that case, I don't have to return anything in the render function.

The below example shows how to use a component to insert a script into the page. I can use it as a reusable utility component to insert different scripts into the page.

import { useCallback, useEffect } from "react"

interface ScriptProps {
    resourceType: 'javascript' | 'css'
    src: string
    id: string

export const ScriptManager = (props: ScriptProps): null => {

    const insertScript = useCallback(() => {
        let link: HTMLScriptElement | HTMLLinkElement
        if (props.resourceType === 'javascript') {
            link = document.createElement('script')
            link.type = 'text/javascript'
            link.setAttribute('src', props.src)
        } else {
            link = document.createElement('link')
        link.id = props.id
    }, [props.id, props.resourceType, props.src])

    useEffect(() => {
    }, [insertScript])
    return null;

The above component can insert a Javascript tag or a CSS link into the page header. I use the useEffect hook to avoid any duplicate inserts. Ideally, I should check to see if the resource exists before inserting it. It is crucial to return null to make this component valid as a React component. Ideally, a React component must return a JSX element, at least an empty fragment. But I don't need that. If I don't return at least null, it will throw the "Its return type 'void' is not a valid JSX element" error when I use this element.

Here is how to use my component to insert Jquery into the page.

import { ScriptManager } from "./script_manager";
const App = () => {
  return <>
export default App;
L Raney
By: L Raney
Lance is a software engineer with over 15 years of experience in full-stack software development.

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